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-.01x^2+.4x+5.8=0
We add all the numbers together, and all the variables
-0.01x^2+.4x+5.8=0
a = -0.01; b = .4; c = +5.8;
Δ = b2-4ac
Δ = .42-4·(-0.01)·5.8
Δ = 0.392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.4)-\sqrt{0.392}}{2*-0.01}=\frac{-0.4-\sqrt{0.392}}{-0.02} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.4)+\sqrt{0.392}}{2*-0.01}=\frac{-0.4+\sqrt{0.392}}{-0.02} $
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